(x+5)(x+3)=x^2

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Solution for (x+5)(x+3)=x^2 equation: 



(x+5)(x+3)=x^2

We move all terms to the left:

(x+5)(x+3)-(x^2)=0

determiningTheFunctionDomain
-x^2+(x+5)(x+3)=0

We add all the numbers together, and all the variables

-1x^2+(x+5)(x+3)=0

We multiply parentheses ..

-1x^2+(+x^2+3x+5x+15)=0

We get rid of parentheses

-1x^2+x^2+3x+5x+15=0

We add all the numbers together, and all the variables

8x+15=0

We move all terms containing x to the left, all other terms to the right

8x=-15

x=-15/8

x=-1+7/8

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